\(\int \frac {(a+c x^2)^p}{d+e x} \, dx\) [736]

Optimal result

Integrand size = 17, antiderivative size = 125 \[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\frac {x \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2},-p,1,\frac {3}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d}-\frac {e \left (a+c x^2\right )^{1+p} \operatorname {Hypergeometric2F1}\left (1,1+p,2+p,\frac {e^2 \left (a+c x^2\right )}{c d^2+a e^2}\right )}{2 \left (c d^2+a e^2\right ) (1+p)} \]

[Out]

x*(c*x^2+a)^p*AppellF1(1/2,1,-p,3/2,e^2*x^2/d^2,-c*x^2/a)/d/((1+c*x^2/a)^p)-1/2*e*(c*x^2+a)^(p+1)*hypergeom([1
, p+1],[2+p],e^2*(c*x^2+a)/(a*e^2+c*d^2))/(a*e^2+c*d^2)/(p+1)

Rubi [A] (verified)

Time = 0.08 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.294, Rules used = {771, 441, 440, 455, 70} \[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\frac {x \left (a+c x^2\right )^p \left (\frac {c x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (\frac {1}{2},-p,1,\frac {3}{2},-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d}-\frac {e \left (a+c x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {e^2 \left (c x^2+a\right )}{c d^2+a e^2}\right )}{2 (p+1) \left (a e^2+c d^2\right )} \]

[In]

Int[(a + c*x^2)^p/(d + e*x),x]

[Out]

(x*(a + c*x^2)^p*AppellF1[1/2, -p, 1, 3/2, -((c*x^2)/a), (e^2*x^2)/d^2])/(d*(1 + (c*x^2)/a)^p) - (e*(a + c*x^2
)^(1 + p)*Hypergeometric2F1[1, 1 + p, 2 + p, (e^2*(a + c*x^2))/(c*d^2 + a*e^2)])/(2*(c*d^2 + a*e^2)*(1 + p))

Rule 70

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(b*c - a*d)^n*((a + b*x)^(m + 1)/(b^(
n + 1)*(m + 1)))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m
}, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] && IntegerQ[n]

Rule 440

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[a^p*c^q*x*AppellF1[1/n, -p,
-q, 1 + 1/n, (-b)*(x^n/a), (-d)*(x^n/c)], x] /; FreeQ[{a, b, c, d, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[n
, -1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 441

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[a^IntPart[p]*((a + b*x^n)^F
racPart[p]/(1 + b*(x^n/a))^FracPart[p]), Int[(1 + b*(x^n/a))^p*(c + d*x^n)^q, x], x] /; FreeQ[{a, b, c, d, n,
p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[n, -1] &&  !(IntegerQ[p] || GtQ[a, 0])

Rule 455

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && EqQ[m
- n + 1, 0]

Rule 771

Int[((d_) + (e_.)*(x_))^(m_)*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Int[ExpandIntegrand[(a + c*x^2)^p, (d/(d
^2 - e^2*x^2) - e*(x/(d^2 - e^2*x^2)))^(-m), x], x] /; FreeQ[{a, c, d, e, p}, x] && NeQ[c*d^2 + a*e^2, 0] &&
!IntegerQ[p] && ILtQ[m, 0]

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {d \left (a+c x^2\right )^p}{d^2-e^2 x^2}+\frac {e x \left (a+c x^2\right )^p}{-d^2+e^2 x^2}\right ) \, dx \\ & = d \int \frac {\left (a+c x^2\right )^p}{d^2-e^2 x^2} \, dx+e \int \frac {x \left (a+c x^2\right )^p}{-d^2+e^2 x^2} \, dx \\ & = \frac {1}{2} e \text {Subst}\left (\int \frac {(a+c x)^p}{-d^2+e^2 x} \, dx,x,x^2\right )+\left (d \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p}\right ) \int \frac {\left (1+\frac {c x^2}{a}\right )^p}{d^2-e^2 x^2} \, dx \\ & = \frac {x \left (a+c x^2\right )^p \left (1+\frac {c x^2}{a}\right )^{-p} F_1\left (\frac {1}{2};-p,1;\frac {3}{2};-\frac {c x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d}-\frac {e \left (a+c x^2\right )^{1+p} \, _2F_1\left (1,1+p;2+p;\frac {e^2 \left (a+c x^2\right )}{c d^2+a e^2}\right )}{2 \left (c d^2+a e^2\right ) (1+p)} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.26 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.05 \[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\frac {\left (\frac {e \left (-\sqrt {-\frac {a}{c}}+x\right )}{d+e x}\right )^{-p} \left (\frac {e \left (\sqrt {-\frac {a}{c}}+x\right )}{d+e x}\right )^{-p} \left (a+c x^2\right )^p \operatorname {AppellF1}\left (-2 p,-p,-p,1-2 p,\frac {d-\sqrt {-\frac {a}{c}} e}{d+e x},\frac {d+\sqrt {-\frac {a}{c}} e}{d+e x}\right )}{2 e p} \]

[In]

Integrate[(a + c*x^2)^p/(d + e*x),x]

[Out]

((a + c*x^2)^p*AppellF1[-2*p, -p, -p, 1 - 2*p, (d - Sqrt[-(a/c)]*e)/(d + e*x), (d + Sqrt[-(a/c)]*e)/(d + e*x)]
)/(2*e*p*((e*(-Sqrt[-(a/c)] + x))/(d + e*x))^p*((e*(Sqrt[-(a/c)] + x))/(d + e*x))^p)

Maple [F]

\[\int \frac {\left (c \,x^{2}+a \right )^{p}}{e x +d}d x\]

[In]

int((c*x^2+a)^p/(e*x+d),x)

[Out]

int((c*x^2+a)^p/(e*x+d),x)

Fricas [F]

\[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{e x + d} \,d x } \]

[In]

integrate((c*x^2+a)^p/(e*x+d),x, algorithm="fricas")

[Out]

integral((c*x^2 + a)^p/(e*x + d), x)

Sympy [F]

\[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\int \frac {\left (a + c x^{2}\right )^{p}}{d + e x}\, dx \]

[In]

integrate((c*x**2+a)**p/(e*x+d),x)

[Out]

Integral((a + c*x**2)**p/(d + e*x), x)

Maxima [F]

\[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{e x + d} \,d x } \]

[In]

integrate((c*x^2+a)^p/(e*x+d),x, algorithm="maxima")

[Out]

integrate((c*x^2 + a)^p/(e*x + d), x)

Giac [F]

\[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\int { \frac {{\left (c x^{2} + a\right )}^{p}}{e x + d} \,d x } \]

[In]

integrate((c*x^2+a)^p/(e*x+d),x, algorithm="giac")

[Out]

integrate((c*x^2 + a)^p/(e*x + d), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+c x^2\right )^p}{d+e x} \, dx=\int \frac {{\left (c\,x^2+a\right )}^p}{d+e\,x} \,d x \]

[In]

int((a + c*x^2)^p/(d + e*x),x)

[Out]

int((a + c*x^2)^p/(d + e*x), x)